Boston Linux & Unix (BLU) Home | Calendar | Mail Lists | List Archives | Desktop SIG | Hardware Hacking SIG
Wiki | Flickr | PicasaWeb | Video | Maps & Directions | Installfests | Keysignings
Linux Cafe | Meeting Notes | Blog | Linux Links | Bling | About BLU

BLU Discuss list archive


[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

awk reg-exp question



On Wed, 2004-01-28 at 15:04, Joshua Pollak wrote:
> #PARAM=wrong_value
> PARAM=value_new # value_old
> 

So basically you want a rule that says "Start with a line, hack off
anything after the #, then do your rule."  Try this:

cat file | sed -e s/#\.\*// | <awk script>

For the first case sed will return a blank line, which should not match
your awk pattern and thus not do anything.

Modify that sed line depending on how you prefer to call it, what shell,
and so forth.  I can never remember what chars I am obligated to escape.

Duane

> ?
> 
> Thanks for the help,
> 
> -Josh





BLU is a member of BostonUserGroups
BLU is a member of BostonUserGroups
We also thank MIT for the use of their facilities.

Valid HTML 4.01! Valid CSS!



Boston Linux & Unix / webmaster@blu.org