URL Parsing Utility?

[will]

This is a 5-line python script:

import sys, urllib
try:
   print urllib.unquote(sys.stdin.readline())
except:
   print "could not be unquoted."


On Mon, 8 Apr 2002, Kent Borg wrote:

> Anyone know of a simple but good little URL parser?  I want something
> that will take an obfuscated URL of the sort included in some spam,
> the ones that are full of %'s and =2e's and stuff like that.
> 
> I want to know who is being promoted in spam so I can complain to
> their provider.  The complaints must be annoying to them, otherwise
> why obscure themselves?
> 
> I can decode the URLs by hand, but that is a slow and a pain.  I could
> let my web browser decode them and then look at the result in netstat
> or something, but I don't want to provide them with any hits on their
> ads, information of my IP address, etc.
> 
> So I want something I can feed
> "http://%36%36%2E%333.%36%30%2E9%31%2Fme%65tp%65o%70%6C%65/" and find
> out the machine it really points to.
> 
> Suggestions?
> 
> 
> Thanks,
> 
> -kb
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> 

-- 
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