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Hi all, I'm writing a bash script which I would like to execute the same script on a linux and a solaris system. but my problem is that the bash executable is in /usr on linux and /usr/bin on solaris. So how do I define the first line #! syntax so that the shell which is executing the script knows where to pick up the executable. For example, the syntax of my simple script under linux would be #!/bin/bash echo Hello World and under solaris would be #!/usr/bin/bash echo Hello World I remember some syntax which would tell the system running the script to look in the path for the shell executable, but I can't remember the syntax and I'm having a hard time finding it searching google. Does anyone know the best solution? Thanks in advance. Steve.
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