PHP question

[mark.richards at massmicro.com (Mark Richards)]

Jerry Feldman wrote:
> 
> The script now works correctly. 
> But, one more quesiton. When I have the debugging turned on, it reports
> that $_POST['VAR'] is not set.
> Notice: Undefined index: VAR in script.php on line 6
> I can fix this with:
> if (isset($_POST['VAR'] )
> 	$VAR = $_POST['VAR'];
> Is there a better way of doing this to avoid the messages. 

Are you certain you're fixing it with
if (isset($_POST['VAR'] ))
	$VAR = $_POST['VAR'];

Should it be

if (isset($_POST['VAR'] ))
	$VAR = $_POST['VAR'];
else
	$VAR - {some default}

Otherwise VAR is left hanging if $_POST['VAR'] is not set.


/m


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